draw resonace structure for oxygen
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O2 has a double bond in its normal form. That is O=O. There are no unpaired electrons in this case are there since there are 2 lone pairs on each oxygen.
However 1 resonance structure would be O−O (result of homolytic cleavage of double bond) where each O is a free radical (a negatively charged one at that). If you have this in hydrogen it is likely going to form hydrogen peroxide.
You could also have O−O where 1 is positive and the other is negative and this is also 2 free radicals.
And finally there is O≡O where both oxygens are positively charged and are free radicals. Why are both positively charged? It is because 3 bonds already to oxygen means 1 lone pair and 5 electrons around oxygen is +1.
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