draw schematic diagram of an electric circuit comprising of three cells and an electric bulb. amitabh plug keen on mode and another with same component but with two bulb in parallel and voltmeter across the combination
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Answer:
The schematic diagram is shown above.
Battery will become of 10V as five cells of 2V are connected in series so voltage of the each cell will be added.
Current flow in the circuit will be
Current (I)=
TotalResistance (R
eq
)
Voltage (V)
R
eq
=20Ω+30Ω
⇒ Current =
50
10
=
5
1
=0.2 A
Current flowing in the circuit is 0.2 Ampere.
So the current flowing in 20Ω resistor will be 0.2 Ampere.
Power consumed by the 30Ω will be
Power=I
2
R
where I is current flowing through the Resistance R=30Ω
⇒Power=0.2
2
×30
⇒Power=1.2J/sec
Hence the Power consumed by 30Ω resistor will be 1.2J/sec
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