draw segment of length √15cm without using pythagoras. please!!!!!
Answers
For u in geometrical representation see above
draw ab=15cm then extend 1cm at c
then find midpoint of ab by compass or perpendicular bisector.
draw a semicircle then perpendicular DB using compass ,take a arc of DB and mark it till E it is 15^-2
Drawn seg length √15 without using pythagoras theorem
Step-by-step explanation:
15 = 3 * 5
Step 1 : Draw a line segment PQ = 5 cm
Step 2 : Draw a perpendicular bisector of PQ and find mid point O
Step 3 : Draw a semi circle Taking OP as radius and O as center using compass
Step 4 : Take 3 cm from P on PQ mark it R
Step 5 : Draw a right angle at R such that it intersect Semicircle at S
PS = √15
Δ PRS ≈ Δ PSQ
as ∠P = ∠P
& ∠PRS = ∠PSQ = 90° (∠PSQ angle in semicircle)
=> PS/PQ = PR/PS
=> PS² = PR * PQ
=> PS² = 3 * 5
=> PS² = 15
=> PS = √15
perpendicular bisector of PQ
using compass Taking width slightly less than PQ draw arcs on both sides taking P as center
Keeping compass width same taking Q as center draw arcs such that it intersects arc drawn in previous step at M & N
Join MN intersecting PQ at O
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