Draw segments XZ and
Proof : By theorem of touching circles,
points X, Z, Y are
∴ ∠XZA @ [Opposite angles]
Let ∠XZA = ∠BZY = a ...(I)
Now, seg XA @ seg XZ
∴ ∠XAZ = = a ...(II) (Isosceles triangle theorem)
Similarly, seg YB @ seg YZ
∴ ∠BZY = = a ...(III)
∠XAZ = [From (I), (II), (III)]
∴ Radius XA ║ radius YB
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