Question

draw structure of nitric acid​

Answer 1

N has 5 valance electron in its outermost shell

O has 6 valance electron in its outermost shell

H has 1 valance electron in its outermost shell

Explanation:

O

||

N+

/ \

O O

/ \

H

Answer 2

Answer:

Explanation:

hno3

first calculate number of electrons

which is 1+5+18

=24

take nitrogen as central atom

 and attach all atoms by  giving bond

see how much electrons left=24-2(bonds)

=24-8

=16

next give electrons to complete octet

means we should give 5 to each oxygen and no electron to hydrogen(already stable)

electrons that will go to oxygen=5*3

=15

electrons remaining=1

lets give that one electron to nitrogen so that it completes octet configuration

final diagram is like this