Chemistry, asked by TbiaSamishta, 1 year ago

Draw structures of the following derivatives: The ethylene ketal of hexan-3-one

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Answered by bhavith19
0
11509 -OEChem-03231907472D 19 18 0 0 0 0 0 0 0999 V2000 3.7320 -0.7500 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 4.5981 0.7500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.4641 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.7320 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.8660 0.7500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 6.3301 0.7500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.0000 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.9966 1.2250 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 4.1996 1.2250 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 5.0656 -0.2249 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 5.8626 -0.2249 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 3.2646 1.2250 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 2.4675 1.2250 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 6.6401 0.2131 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 6.8671 1.0600 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 6.0201 1.2869 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 1.6900 0.7869 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 1.4631 -0.0600 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 2.3100 -0.2869 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 1 4 2 0 0 0 0 2 3 1 0 0 0 0 2 4 1 0 0 0 0 2 8 1 0 0 0 0 2 9 1 0 0 0 0 3 6 1 0 0 0 0 3 10 1 0 0 0 0 3 11 1 0 0 0 0 4 5 1 0 0 0 0 5 7 1 0 0 0 0 5 12 1 0 0 0 0 5 13 1 0 0 0 0 6 14 1 0 0 0 0 6 15 1 0 0 0 0 6 16 1 0 0 0 0 7 17 1 0 0 0 0 7 18 1 0 0 0 0 7 19 1 0 0 0 0 M END > <PUBCHEM_COMPOUND_CID> 11509 > <PUBCHEM_COMPOUND_CANONICALIZED> 1 > <PUBCHEM_CACTVS_COMPLEXITY> 57.2 > <PUBCHEM_CACTVS_HBOND_ACCEPTOR> 1 > <PUBCHEM_CACTVS_HBOND_DONOR> 0 > <PUBCHEM_CACTVS_ROTATABLE_BOND> 3 > <PUBCHEM_CACTVS_SUBSKEYS> AAADccBgIAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGgAAAAAACASAgAACAAAAAAAIAIAQAAAAAAAAAAAAAAEAAAAAABIAAAAAAAAAAAAAAAEAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA== > <PUBCHEM_IUPAC_OPENEYE_NAME> hexan-3-one > <PUBCHEM_IUPAC_CAS_NAME> 3-hexanone > <PUBCHEM_IUPAC_NAME> hexan-3-one > <PUBCHEM_IUPAC_SYSTEMATIC_NAME> hexan-3-one > <PUBCHEM_IUPAC_TRADITIONAL_NAME> hexan-3-one > <PUBCHEM_IUPAC_INCHI> InChI=1S/C6H12O/c1-3-5-6(7)4-2/h3-5H2,1-2H3 > <PUBCHEM_IUPAC_INCHIKEY> PFCHFHIRKBAQGU-UHFFFAOYSA-N > <PUBCHEM_XLOGP3_AA> 1.2 > <PUBCHEM_EXACT_MASS> 100.089 > <PUBCHEM_MOLECULAR_FORMULA> C6H12O > <PUBCHEM_MOLECULAR_WEIGHT> 100.161 > <PUBCHEM_OPENEYE_CAN_SMILES> CCCC(=O)CC > <PUBCHEM_OPENEYE_ISO_SMILES> CCCC(=O)CC > <PUBCHEM_CACTVS_TPSA> 17.1 > <PUBCHEM_MONOISOTOPIC_WEIGHT> 100.089 > <PUBCHEM_TOTAL_CHARGE> 0 > <PUBCHEM_HEAVY_ATOM_COUNT> 7 > <PUBCHEM_ATOM_DEF_STEREO_COUNT> 0 > <PUBCHEM_ATOM_UDEF_STEREO_COUNT> 0 > <PUBCHEM_BOND_DEF_STEREO_COUNT> 0 > <PUBCHEM_BOND_UDEF_STEREO_COUNT> 0 > <PUBCHEM_ISOTOPIC_ATOM_COUNT> 0 > <PUBCHEM_COMPONENT_COUNT> 1 > <PUBCHEM_CACTVS_TAUTO_COUNT> -1 > <PUBCHEM_COORDINATE_TYPE>
Answered by sneha20003
2

i hope it helps u my answer is correct I hope

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