Physics, asked by wwwkhyatiraniborah, 4 months ago

draw the circuit diagram for the comparison of e. m. f. 's of two cells by a potentiometer

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Answered by kamakshiprabhu04
4

Answer:

Comparison of emf of two cells: First of all the ends of potentiometer are connected to a battery B1, key K and rheostat Rh such that the positive terminal of battery B1 is connected to end A of the wire. This completes the primary circuit.

here is the image of diagram

I hope it's helpful

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