Question

draw the diagram of the path followed by a steel ball of mass 10 g being thrown horizontally from the top of a tower of height 60 cm. Give the name of path followed.

Answer 1

Answer :

Given that,

The mass m = 100 g

Velocity v = 100 km/h

Height h = 75 m

A steel ball is thrown in horizontally.

So, The horizontal component of the velocity will be same as initial velocity.

The ball will fall on the ground at a distance equal to range.

The range given by

R = u\times(\dfrac{2h}{g})^{\dfrac{1}{2}}R=u×(

g

2h

)

2

1

R= 100\times\dfrac{5}{100}\times(\dfrac{2\times75}{9.8})^{\dfrac{1}{2}}R=100×

100

5

×(

9.8

2×75

)

2

1

R = 19.56\ mR=19.56 m

The range is 19.56 m.