Question

Draw the diagram showing the electronic configuration of the element oxygen (O = 8)​

Answer 1

Answer:

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Answer 2

Answer:

• The electron configuration for oxygen is: 1s22s22p4

Explanation:

• Scientist Niels Bohr was the first to give an idea of the atom’s orbit. He provided a model of the atom in 1913. The complete idea of the orbit is given there. The electrons of the atom revolve around the nucleus in a certain circular path. These circular paths are called orbit(shell). These orbits are expressed by n. [n = 1,2,3,4 . . . The serial number of the orbit]
• K is the name of the first orbit, L is the second, M is the third, and N is the name of the fourth orbit. The electron holding capacity of each orbit is 2n2.
• n = 1 for K orbit.
• The maximum electron holding capacity in K orbit is 2n2 = 2 × 12 = 2.
• For L orbit, n = 2.
• The maximum electron holding capacity in L orbit is 2n2 = 2 × 22 = 8.
• n=3 for M orbit.

• The maximum electrons holding capacity in M orbit is 2n2 = 2 × 32 = 18.
• n=4 for N orbit.
• The maximum electrons holding capacity in N orbit is 2n2 = 2 × 42 = 32.
• Therefore, the maximum electron holding capacity in the first shell is two, the second shell is eight and the 3rd shell can have a maximum of eighteen electrons. The atomic number is the number of electrons in that element.
• Oxygen has 6 electrons so its electronic configuration will be. 2, 6
• The electron configuration for oxygen is: 1s22s22p4

Link

• https://brainly.in/question/44126201