Question

draw the figure and show that angle BOC =90°+½ angle A where OB and OC are angle bisector of angle ABC and and angle ACB in triangle ABC​

Answer 1

Answer:

Step-by-step explanation:

OB and OC are the bisectors of ∠B and ∠C

So x=∠B/2 and y=∠C/2

In Δ OBC

x+y+p=180

∠B/2 +∠C/2+p=180

(√B+∠C)/2 +P=180

p-= 180-(√B+∠C)/2

=180-(180-√A)/2

=180-90+∠A/2

p=90+1/2 ∠BAC

∠BOC =  90 + 1/2 ∠BAC