Question

Draw the figure for given situation of eye ball ,suppose an object is at 25cm before eye and minimum focal length of eye is 2.27cm

Answer 1

Explanation:

Given that,

The distance of the object u = -25 cm

Focal length f = 2.27 cm

Using lens formula

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{2.27}=\dfrac{1}{v}-\dfrac{1}{-25}$

$\dfrac{1}{v}= \dfrac{4}{10}$

$v = \dfrac{10}{4}$

$v = 2.5\ cm$    

The distance of the image is greater than the focal length so its defect is hypermetropia.

Therefore, we will use the convex lens for correcting its defect.