Question

draw the following orbitals having xy, z axes and propane psi s= orbital all the p,d,and f orbitals sp, sp²and sp³ orbitals​

Answer 1

Answer:

In the given compound,

There is 2 sp

3

, 2 sp

2

and 3 sp hybridized carbon atom.

Hence,number of sp

3

hybrid orbitals =4+4,

number of sp

2

hybrid orbitals =3+3,

numberof sp hybrid orbitals =2+2+2.

Hence ratio of sp:sp

2

:sp

3

=6:6:8=3:3:4

Hence, the option (D) is correct.

Answer 2

Answer:

D

Explanation:

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