draw the graph 3x+2y=5 on the graph paper
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Step-by-step explanation:
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Answer:
A pair of linear equations in two variables will be represented by two straight lines taken together.
For two lines in a plane following three possibilities can happen:
1.The two lines representing a pair of linear equations will intersect at a point.
2. The two lines representing a pair of linear equations will not intersect or they are parallel to each other.
3. The two lines representing a parallel equations in two variables will be coincident they overlap each other.
•In order to represent the pair of linear equation graphically we need two points on the line representing each equation.
• Prepare the proper table of at least 2 solutions for both the equations.
•Draw the graph of both the question on the same graph paper with same scale of representation.
SOLUTION:
Given pair of Linear Equations are:
3x - 4y +3 =0 ……………….(1)
3x + 4y - 21 = 0 …………….(2)
Put x= 3 in eq 1
3x - 4y +3 =0
3×3 - 4y +3= 0
9 - 4y = - 3
9 +3 = 4y
12 = 4y
y = 12/4= 3
A(3, 3)
Put y= 0 in eq 1
3x - 4 × 0 = -3
3x = -3
x =- 3/3 = -1
B(-1,0)
Put x= 3 in eq 2
3x + 4y -21 =0
3×3 + 4y = 21
9 + 4y = 21
4y = 21 -9
4y = 12
y = 12/4= 3
A(3, 3)
Put y= 0 in eq 2
3x + 4×0= 21
3x + 0 = 21
3x = 21
x = 21/3
x = 7
x = 2
C(7,0)
TABLE AND GRAPH are on the ATTACHMENT.
The coordinates of the vertices of ∆ABC are A(3, 3) , B(-1,0) & C(7,0)
Area of ∆ ABC = ½ (base × height)
Area of ∆ ABC = ½ (AM × BC)
[From the graph , AM = 3 , BC = 8]
Area of ∆ ABC = ½ (3 × 8) = 24/2 = 12 sq units.
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Step-by-step explanation: