Draw the graph for following situations
a. Object at zero acceleration is (s-t, v-t)
b. Obiect falling freely under gravity (v-t)
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Explanation:
1) object at zero acceleration :
a) s-t Graph:
Let the velocity be 'u' .
So,
S= ut
Linear equation
=> Represents straight line with finite slope.
b) v-t Graph:
a=0;
Using Newton's Equation,
v=u+at=u (constant)
=> straight line with zero slope.
2) Object falling freely under gravity.
a = -g (acceleration due to gravity)
Assuming zero initial velocity.
using Newton's Equation ,
v=u+at
= 0-gt
=> straight line with negative slope.
All figures are attached respectively.
Attachments:
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