Question

draw the graph for the following linear equation:4=x+3y​

Answer 1

Step-by-step explanation:

Answer

4x−3y+4=0

4x+3y−20=0

In eqn 1 put x=0,y=

3

4

,(0,

3

4

)

put y=0,x=−1 (−1,0)

In eqn 2 put x=0,y=

3

20

. (0,

3

20

)

puty=0,x=5.(5,0)

So, graph

Point of intersection of eqn 1 & 2

1+2

⇒8x=16

x=2,y=4

So area bounded by eqn 1.2 and x−axis

2

1

(Base \times height )

=

2

1

(6×4)

=12 sq.units