Math, asked by XxunknownboyxX2, 14 hours ago

Draw the graph for the following table of values of time (in hours) and distances (in km) covered by a car. Time (in hours) Distance (in 7:00 8:00 9:00 10:00 km) 60 120 180 240 From the graph, find: ) The distance covered by the car during the period 7:00 to 8:00. ii) At what time the car would have covered 180 km?​
shreya????​

Answers

Answered by rachit7verma
0

Step-by-step explanation:

Use suitable identity to find the product: (x + 8)(x - 10)Factorise: z2

- 32z - 105.The polynomials ax3

+ 3x2

- 3 and 2x3

- 5x + a when divided by (x - 4) leave the remainders R1

and R2 respectively. Find the values of a if R1 + R2 = 0If a + b + c = 9 and ab + bc + ca = 26, find a2

+ b2

+ c2Determine polynomial has x - 2 a factor: 4x2

+ x - 2Factorize: x2

- - 6Factorize: x2

- - 6 3x [2] – √

7. If a + b + c = 9 and ab + bc +If a + b + c = 9 and ab + bc + ca = 26, find a2

+ b2

+ c23xDetermine polynomial has x - 2 a factor: 4x2

+ x - 2Determine polynomial has x - 2 a factor: 4x2

+ x - 2Factorise: z2

- 32z - 105.Use suitable identity to find the product: (x + 8)(x - 10)The polynomials ax3

+ 3x2

- 3 and 2x3

- 5x + a when divided by (x - 4) leave the remainders R1

and R2 respectively. Find the values of a if R1 + R2 = 0The polynomials ax3

+ 3x2

- 3 and 2x3

- 5x + a when divided by (x - 4) leave the remainders R1

and R2 respectively. Find the values of a if R1 + R2 = 0Factorize 2y + − 2y − 1Factorize 2y + − 2y − 1

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