Question

Draw the graph of (1) P(x)=x2-x-6 (2) P(x)=6-x-x2 and find zeroes in each case . what do you notice​

Answer 1

Explanation:

ANSWER

Given,

y=x

2

−x−6

x

2

−x−6=0

→(x−3)(x+2)=0

→x=−2,3

y=6−x−x

2

6−x−x

2

=0

→(x+3)(x−2)=0

→x=−3,2