Question

Draw the graph of 2 lines, whose equations are 3x+2y-6=0 and x+2y-6=0 on the same graph paper. Find area of triangle formed by 2 lines and x-axis.

Answer 1

hey u here yrs ànswer

not having graph currently I have drawn it roughly so when u draw the fair graph u can find the area easily

hope this will help you and if u are satisfied with my answer plz mark me as bRainlist

Answer 2

Given : Equations of the line 3x + 2y - 6 = 0 and x + 2y - 6 = 0

To Find : Area of the triangle formed by 2 lines and x-axis.

Solution:

Equation of the first line is 3x + 2y - 6 = 0

Slope-intercept form of the equation is,

2y = -3x + 6

$y=\frac{-3}{2}x+3$ ---------(1)

Table for input-output values will be,

x   0     2    4  

y   3     0   -3

Similarly, second equation is,

x + 2y - 6 = 0

2y = -x + 3

y = $-\frac{1}{2}x+3$ --------(2)

Table for input-output values will be,

x      0      2      6

y      3      2      0

Now by plotting these points we get a triangle with vertices (0, 3), (2, 0) and (6, 0)

Area of the given triangle = $\frac{1}{2}(\text{base})(\text{height})$

Base = 4 units

Height = 3 units                                        

Area = $\frac{1}{2}(4)(3)$ = 6 square units