Question

Draw the graph of 2(x+3) -3(y+1) =0​

Answer 1

Answer:

know 5x5 = 25 and 6x6 = 36, so the square root of 30 is somewhere between 5 and 6. We'll start out by guessing 5.5.

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Answer 2

$\large\underline{\sf{Solution-}}$

Given equation of line is

$\rm :\longmapsto\:2(x + 3) - 3(y + 1) = 0$

$\rm :\longmapsto\:2x +6 - 3y - 3 = 0$

$\rm :\longmapsto\:2x - 3y + 3 = 0$

$\rm :\longmapsto\:2x = 3y - 3$

Substituting 'y = 1' in the given equation, we get

$\rm :\longmapsto\:2x = 3(1) - 3$

$\rm :\longmapsto\:2x = 3 - 3$

$\rm :\longmapsto\:2x = 0$

$\rm :\longmapsto\:x = 0$

Substituting 'y = - 1' in the given equation, we get

$\rm :\longmapsto\:2x = 3( - 1) - 3$

$\rm :\longmapsto\:2x = - 3 - 3$

$\rm :\longmapsto\:2x = - 6$

$\rm :\longmapsto\:x = - 3$

Substituting 'y = 0' in the given equation, we get

$\rm :\longmapsto\:2x = 3(0) - 3$

$\rm :\longmapsto\:2x = - 3$

$\rm :\longmapsto\:x = - 1.5$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 1 \\ \\ \sf - 3 & \sf - 1 \\ \\ \sf - 1.5 & \sf 0 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points (0 , 1), (- 3, - 1) & (- 1.5 , 0)

➢ See the attachment graph.