Draw the graph of a function f(x)=x^2+4x-1
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a=−1,b=4,c=−1. As a is negative, the parabola should open down.
Vertex: x=−b/2a=2. Putting this value of x, we get y=3.
Hence, the vertex of the parabola is (2,3).
Assume two values of x as follows and find the corresponding values of y.
x 1 −1
y 2 −6
Points obtained are (1,2) and (−1,−6).
Points obtained are (2,3) (vertex), [1,2], and [−1,−6].
Symmetry of parabola: Mirror image points of (1,2) and (−1,−6) are (3,2) and (5,−6), respectively.
Now, sketch the parabola as shown in Fig.
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