Question

draw the graph of each equation given below. Also, Find the Co-ordinates of the point where the graph cuts the Co-ordinate axis: 1)6x-3y=12
2)4y-x=8
3)2x+y=6
4)3x+2y+6=0

Answer 1

In equation 1) 6x-3y=12 put x=o than we get y=4 In equation than put y=0 than we get y=2 In equation 2) 4y-x=8 put x=0 than we get y=2 in equation than put y=0 than we get x=8 In equation 3) 2x+y=6 put x=0 we get y=6 in equation than put y=0 than we get x=3 In equation 4)3x+2y+6=0 put x=0 than we get y=3 in equation than put y=0 than we get x=2 Therefore put this values in graph

Answer 2

1) 6x-3y=12
suppose x = 1 then put value
6×1-3y=12
6-3y=12
-3y= 12 -6
-3y=6
by changing sign
3y=-6
y=-6/3
y=-2


x=2
6×2-3y=12
12-3y =12
-3y=12 -12
-3y= 0
y =0/-3
y = 0


x= 3
6×3-3y=12
18-3y =12
-3y= 12-18
-3y=-6
y=-6/-3
y= 2



like that u slove all....you suppose x= any number infact u suppose in negative also.....then you solve all the problem....and in graph you put x-aixs and y-axis....from the centre of the graph ....and from the given equation you get x and y you put value and draw the graph.....from first equation you will get 3 co ordinate x and y .....then u put the value....and then jion 3 coordinate point you will get a straight line...your graph is ready.......



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