Draw the graph of each of the equation 2x-3y+5=0 and 5x+4= 0 amd find the quardinates of the point where of the point where the lines meet
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Given 6x−3y=12
⟹3(2x−y)=12
⟹2x−y=4
⟹y=2x−4⋯(1)
To draw the graph , we need atleast two solutions
Also to find the coordinates of the points where the graph cuts the coordinate axes,put x=0 and y=0 respectively
Put x=0 in (1)
⟹y=2(0)−4=0−4=−4
(0,−4) is the solution of given line
Put y=0
⟹0=2x−4
⟹2x=4
⟹x=2
(2,0) is the solution of given line
With these two solutions we can draw graph of 6x−3y=12
(2,0) & (0,−4) are the points where the graph cuts the coordinate axes
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