Math, asked by adhubala4174, 6 hours ago

Draw the graph of each of the following linear equations in two variables:6x-2y=7

Answers

Answered by jayshree1981
0

Answer:

matee I have different solutions but the steps are same you can understand the sequence and solve and I don't know about graph -n-"

Step-by-step explanation:

Given 6x−3y=12

⟹3(2x−y)=12

⟹2x−y=4

⟹y=2x−4⋯(1)

To draw the graph , we need atleast two solutions

Also to find the coordinates of the points where the graph cuts the coordinate axes,put x=0 and y=0 respectively

Put x=0 in (1)

⟹y=2(0)−4=0−4=−4

(0,−4) is the solution of given line

Put y=0

⟹0=2x−4

⟹2x=4

⟹x=2

(2,0) is the solution of given line

With these two solutions we can draw graph of 6x−3y=12

(2,0) & (0,−4) are the points where the graph cuts the coordinate axes

Hope it helps you

Answered by mathdude500
2

\large\underline{\sf{Solution-}}

Given linear equation is

\rm :\longmapsto\:6x - 2y = 7

can be rewritten as

\rm :\longmapsto\:2y = 6x - 7

On substituting x = 0, we get

\rm :\longmapsto\:2y = 6(0) - 7

\rm :\longmapsto\:2y =  - 7

\bf\implies \:y =  - 3.5

Now,

On substituting x = 1, we get

 \red{\rm :\longmapsto\:2y = 6(1) - 7}

 \red{\rm :\longmapsto\:2y = 6 - 7}

 \red{\rm :\longmapsto\:2y =  - 1}

 \red{\bf\implies \:y =  - 0.5}

Now,

On substituting x = 2, we get

 \green{\rm :\longmapsto\:2y = 6(2) - 7}

 \green{\rm :\longmapsto\:2y = 12 - 7}

 \green{\rm :\longmapsto\:2y = 5}

 \green{\bf\implies \:y = 2.5}

Hᴇɴᴄᴇ,

Pair of points of the given equation are shown in the below table.

 \purple{\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf  - 3.5 \\ \\ \sf 1 & \sf  - 0.5 \\ \\ \sf 2 & \sf 2.5 \end{array}} \\ \end{gathered}}

➢ Now draw a graph using the points

➢ See the attachment graph.

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