Question

draw the graph of eq. x/3 + y/4 = 1

Answer 1

$we \: have \\ \frac{x}{3} + \frac{y}{4} = 1 \\ 4x + 3y = 12$

$4x = 12 - 3y$

$\frac{12 - 3y}{4}$

$putting \: y = 0 in(i) \\ we \: get \: x = \frac{12 - 3 \times 0}{4} = 0$

$putting \: y \: = - 4 in(ii) \\ we \: get \: x = \frac{12 - 3 \times 4}{4} = 0$

thus, we obtained that the coordinates of 2 points on the line represents by the equation

$\frac{x}{3} + \frac{y}{4} = 1$