Math, asked by amanrock33, 1 year ago

draw the graph of equation 5 x minus Y is equal to 5 and 3 x minus Y is equal to 3 determine the co-ordinate of the vertices of Triangle formed by these lines and y axis

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Answers

Answered by ShuchiRecites
82
\textit{ \textbf{ Hello Mate! }}

In equation 5x - y = 5

Keep once, x = 0 and y = 0

5(0) - y = 5

y = - 5

5x - (0) = 5

x = 1

\textsf{ Coordinates : (0,-5) ; (1,0) }

In equation 3x - y = 3

Keep x once = 0, y = 0

3(0) - y = 3

y = - 3

3x - (0) = 3

x = 1

\textsf{ Coordinates : (0,-3) ; (1,0) }

\texttt{ Have great future ahead! }


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Answered by DelcieRiveria
27

Answer:

The vertices of triangle are (0,-5), (0,-3) and (1,0).

Step-by-step explanation:

The given equations of lines are

5x-y=5         .... (1)

3x-y=3          ..... (2)

We have to find the co-ordinate of the vertices of triangle formed by these lines and y axis.

Put x=0, in the given equations to find the y-intercept.

5(0)-y=5\Rightarrow y=-5

The y-intercept of first line is (0,-5).

3(0)-y=3\Rightarrow y=-3

The y-intercept of second line is (0,-3).

Subtract equation (2) from equation (1), to find the intersection point of both equations.

5x-y-(3x-y)=5-3

5x-y-3x+y=2

2x=2

x=1

Substitute x=1 in equation (1).

5(1)-y=5

y=5-5

y=0

The intersection point of both lines is (1,0).

Therefore the vertices of triangle are (0,-5), (0,-3) and (1,0).

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