Draw the graph of equation 5x + 3y = 4 and check whether a) x = 2, y = 5 b) x = −1, y = 3 are solution.
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Draw the graph
2x+3y=5
x 1 7 13 y 1-3 -7
using this point draw a graph
let x = 1
2(1)+3y=5
3y=5−2
3y=3
y=1
let x = 7
2(7)+3y=5
3y=5−14
3y=−9
y=−3
let x = 13
2(13)+3y=5
26+3y=5
3y=5−26
3y=−21
y=−7
(-3, 4) & put x = -3
2(−3)+3y=5
−6+3y=5
3y=11
y=311=4
so (-3, 4) is not solution.
(7,-3) put x = 7
2(7)+3y=5
3y=5−14
3y=−9
y=−3 is solution
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