Question

Draw the graph of equation 5x + 3y = 4 and check whether

(a) x = 2, y = 5

(b) x = −1, y = 3 are solutions.​

Answer 1

Answer:

R.E.F.Image.

Draw the graph

2x+3y=5

x 1 7 13

y 1 -3 -7

using this point draw a graph

let x = 1

2(1)+3y=5

3y=5−2

3y=3

y=1

let x = 7

2(7)+3y=5

3y=5−14

3y=−9

y=−3

let x = 13

2(13)+3y=5

26+3y=5

3y=5−26

3y=−21

y=−7

(-3, 4) & put x = -3

2(−3)+3y=5

−6+3y=5

3y=11

y=

3

11



=4

so (-3, 4) is not solution.

(7,-3) put x = 7

2(7)+3y=5

3y=5−14

3y=−9

y=−3 is solution.

solution

Answer 2

Answer:

(b) is correct.

Step-by-step explanation:

5x+3y=4

if x=-1 and y=3

then put in equation

Now, L.H.S.

=5(-1)+3(3)

=-5+9

=4 which is R.H.S

Hence Proved.