Math, asked by sk8506924881, 8 months ago

Draw the
graph of following
linear equations:
2x +y=6,
х+у =4,
2x-3y=6​

Answers

Answered by hayarunnisamuhammedp
3

2nd QUESTION

Draw the graph of the following linear equations in two variables:- x + y = 4

SOLUTION

It can be observed that x = 0, y = 4 and x = 4, y = 0 are solutions of the above equation. Therefore, the solution table is as follows.

x 0 4

y 4 0

The graph of this equation is constructed as follows.

3rd QUESTION...

3 = 2x +y

3 = 2x +y

3 = 2x + y

⇒ y = 3 – 2x

Table of solutions

We plot the points (0, 3) and (1, 1) on the graph paper and join the same by a ruler to get the line which is the graph of the equation 3 = 2x + y.

1st question

one way is to find the intercepts, that is where the graph

crosses the x and y axes

let x = 0, in the equation for y-intercept

let y = 0, in the equation for x-intercept

x=0

⇒0−y=6

⇒y=−6←

y-intercepty=0

⇒2x−0=6

⇒x=3←x-interceptplot

(0,−6) and (3,0)

draw a straight line through them for graph

graph{(y-2x+6)((x-0)^2+(y+6)^2-0.04)((x-3)^2+(y-0)^2-0.04)=0 [-28.88, 28.84, -14.42, 14.46]}

Step-by-step explanation:

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