Question

draw the graph of liner equation 3x+4y=6​

Answer 1

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Answer 2

Answer:

According to the question, We get the equation, 3x + 4y = 6. We need at least 2 points on the graph to draw the graph of this equation, Thus, the points the graph cuts (i) x-axis Since, the point is on x axis, we have, y = 0. Substituting y = 0 in the equation, 3x + 4y = 6, We get, 3x + 4×0 = 6 ⇒ 3x = 6 ⇒ x = 2 Hence, the point at which the graph cuts x-axis = (2, 0). (ii) y-axis Since, the point is on y axis, we have, x = 0. Substituting x = 0 in the equation, 3x + 4y = 6, We get, 3×0 + 4y = 6 ⇒ 4y = 6 ⇒ y = 6/4 ⇒ y = 3/2 ⇒ y = 1.5 Hence, the point at which the graph cuts x-axis = (0, 1.5). Plotting the points (0, 1.5) and (2, 0) on the graph.

Step-by-step explanation: