Question

Draw the graph of p(x) =x^2-6x-9 and find the zeroes it's zeroes. ​

Answer 1

Answer:

Zeroes are x = [+6 ± 6(2)^0.5] / 2

Step-by-step explanation:

First find "D". So D=( b² - 4ac) =6²- 4×1×(-9) which will be equal to 72 or (6²× 2)

Now for the roots we have a formula x={ -b ±(D) ^0.5} /2a

On finally substituting the values of a, b, c & D from the equation we get this.....

x = [+6 ± 6(2)^0.5] / 2

Now for graphical method......

Lets assume that y= x²-6x-9

Now put random values for x and we will get y..

Plot the points on the graph and the point where y axis is zero on the graph, will be the zero for the polynomial....

And that's all

Thank you