draw the graph of p(x)=x square -x-12 and find the zeroes .justify your answer
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Answer:
p(x)=x^2-x-12
Explanation:
p(x)=x^2-x-12
=x^2+3x-4x-12
=x(x+3)-4(x+3)
=(x-4)(x+3)
x-4=0 p(4)= (4)^2 -4-12
= 16-4-12
= x = 4 =16-16
=0
similarly x+3 is also a zero .
Hence ( x-4) and (x+3) are zeroes of the polynomial
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