Hindi, asked by kusum444, 9 months ago

draw the graph of polynomial FX equal to minus 3 X square + 2 x minus one​

Answers

Answered by TakenName
12

To draw a graph of quadratic polynomial

we need : Vertex & Line of symmetry

To find the vertex : complete the square

CALCULATION METHOD

F(x)=3x^2-2x+1

=3(x^2-\frac{2}{3} x)+1

=3(x^2-\frac{2}{3}x+\frac{1}{9} -\frac{1}{9} )+1

=3(x-\frac{1}{3} )^2-\frac{3}{9} +1

=3(x-\frac{1}{3} )^2+\frac{2}{3}

The coordinate of the vertex is (x,y)=(\frac{1}{3} ,\frac{2}{3} )

Also, the line of symmetry is x=\frac{1}{3}

Also it is graphed from desmos.com

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Answered by jainvinod99046
0

Answer:

To draw a graph of quadratic polynomial

To draw a graph of quadratic polynomialwe need : Vertex & Line of symmetry

To draw a graph of quadratic polynomialwe need : Vertex & Line of symmetryTo find the vertex : complete the square

CALCULATION METHOD

F(x)=3x^2-2x+1F(x)=3x2−2x+1

=3(x^2-\frac{2}{3} x)+1=3(x2−32x)+1

=3(x^2-\frac{2}{3}x+\frac{1}{9} -\frac{1}{9} )+1=3(x2−32x+91−91)+1

=3(x-\frac{1}{3} )^2-\frac{3}{9} +1=3(x−31)2−93+1

=3(x-\frac{1}{3} )^2+\frac{2}{3}=3(x−31)2+32

The coordinate of the vertex is (x,y)=(\frac{1}{3} ,\frac{2}{3} )(x,y)=(31,32)

Explanation:

Also, the line of symmetry is x=\frac{1}{3}x=31

Also, the line of symmetry is x=\frac{1}{3}x=31Also it is graphed from desmos.com

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