Question

draw the graph of polynomial p(x) = x²-4x +3 and also find its zero

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Answer 1

Answer:

x²-4x+3

= x²-3x-x+3

= x(x-3)-1(x+3)

= (x-3)(x-1)

x-3 = 0

x = 3

x-1 = 0

x = 1

1 and 3 are the zeros

Answer 2

We need to recall the following definition.

• The zeros of a polynomial are
• the value of a variable that makes the polynomial true.

Given:

$p(x)=x^2-4x+3$

Simplify the polynomial.

$x^2-4x+3=0$

$x^2-3x-x+3=0$

$x(x-3)-1(x-3)=0$

$(x-3)(x-1)=0$

$x-3=0$  OR  $x-1=0$

$x=3$  OR  $x=1$

Hence, the zeros of the polynomial are $x=1$ and $x=3$.

The graph of the polynomial is as follows: