Draw the graph of straight line given by the equation x/2 + y/3 = 1. Calculate the area of triangle formed by the line drawn and the coordinate axes
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Clearly, the equation intercepts the x-axis at (2,0) and the y-axis at (0,3), therefore we obtain a Right Angled triangle with one side 2 units and the other 3 units and the area thus obtained is: (1/2)*(2)*(3) = 3 sq.units.
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Answer:
on solving equation is 3x + 2y = 6
on making a graph of this it intersect x axis at (2,0) and y axis at (0,3)
therefore area of triangle is 1/2 *
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