Question

Draw the graph of the equation 2(x+1)=3(y-1)-4 and check whether the point (3,-1) lies on the line.

Answer 1

Step-by-step explanation:

2(x+1) = 3(y-1)

2x + 2 = 3y - 3

2x +2 - 3y + 3 = 0

2x - 3y + 5 = 0

To check whether the points (x,y) = (3,-1) lies on the line substitute x,y in the obtained equation

2x - 3y + 5 = 0

2(3) - 3(-1) + 5 = 0

6+3+5 ≠ 0

14≠0

hence, the point does not lie on the line

Answer 2

Step-by-step explanation:

2(x+1)=3(y-1)-4

2x+2=3y-3-4

2x+2+7=3y

y=2x+3/3

x 0 2

y 3 5

(3, -1) coordinates do not lie on the line