Draw the graph of the equation 2(x+1)=3(y-1)-4 and check whether the point (3,-1) lies on the line.
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Answer:
2(x+1) = 3(y-1)
2x + 2 = 3y - 3
2x +2 - 3y + 3 = 0
2x - 3y + 5 = 0
To check whether the points (x,y) = (3,-1) lies on the line substitute x,y in the obtained equation
2x - 3y + 5 = 0
2(3) - 3(-1) + 5 = 0
6+3+5 ≠ 0
14≠0
hence, the point does not lie on the line
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