Question

draw the graph of the equation 2(x+3)-3(1+y)=0​

Answer 1

Step-by-step explanation:

2x+6-3+3y=

2x+3x=-6+3

5x=-3

x=5\3

Answer 2

Step-by-step explanation:

Given :-

2(x+3)-3(1+y)=0

To find :-

Draw the graph of the equation?

Solution :-

Given equation is 2(x+3)-3(1+y)=0

=>( 2x+6 ) - (3+3y) = 0

=> 2x+6 -3 -3y = 0

=> 2x-3y+3 = 0

The equation is 2x-3y+3 = 0

Graph of the equation :-

The equation is 2x-3y+3 = 0

=> 3y = 2x+3

=> y = (2x+3)/3

If x = 0 then y = (2×0+3)/3

=> y = (0+3)/3

=> y = 3/3

=> y = 1

The point = (0,1)

If x = 6 then y = (2×6+3)/3

=> y = (12+3)/3

=> y = 15/3

=> y = 5

The point = (6,5)

If x = -6 then y = (2×-6+3)/3

=> y = (-12+3)/3

=> y = -9/3

=> y = -3

The point = (-6,-3)

The points are (0,1),(6,5),(-6,-3),

Observation:-

On plotting the points on the graph we get a straight line .

See the above attachment

Result:-

→ The graph of the given equation is a straight line