Draw the graph of the equation 2x-3y=10
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2x+3y=12⋯(1)
To draw the graph ,we need at least two solutions of the equation
Put x=0 in (1)
2(0)+3y=12
⟹3y=12
⟹y=4
So (0,4) is a solution of the equation
Put y=0 in (1)
2x+3(0)=12
⟹2x=12
⟹x=6
So (6,0) is a solution of the equation
With these two equations we can draw graph of 2x+3y=12
from the graph
(i) when y=3 then x=1.5
So, point is (1.5,3)
(ii) when x=−3 then y=6
So, point is (−3,6
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