Math, asked by beatstartup26711, 11 months ago

Draw the graph of the equation 2x+3y=12. From the graph, find the coordinates of the point.
(i) whose y-coordinates is 3.
(ii) whose x-coordinate is -3.

Answers

Answered by hukam0685
1

Answer:

(i) whose y-coordinates is 3

Ans:x=1.5

(ii) whose x-coordinate is -3

Ans: y=6

Step-by-step explanation:

To find the graph of line,put the values of x and find the values of y.

2x + 3y = 12 \\  \\ y =  \frac{12 - 2x}{3}  \\  \\

put x=0

y=12/3=4

(0,4)

put x=3

y=6/3=2

(3,2)

put x=-3

y=18/3=6

(-3,6)

Mark these points and join with a straight line,as shown in attached graph.

(i) whose y-coordinates is 3

Ans:x=1.5

(ii) whose x-coordinate is -3

Ans: y=6

Hope it helps you.

Attachments:
Answered by bestwriters
2

The coordinates of the point are:

(i) The point whose y-coordinates is 3 then its x-coordinates is 3/2

(ii) The point whose x-coordinate is -3 then its y-coordinates is 6

Step-by-step explanation:

From question, the equation given is:

2x + 3y = 12

2x = 12 - 3y

x = (12 - 3y)/2

On putting y = 2, then we get,

x = (12 - 3(2))/2 = (12 - 6)/2 = 6/2 = 3

Thus, the point is (3, 2).

On putting y = 4, then we get,

x = (12 - 3(4))/2 = (12 - 12)/2 = 0/2 = 0

Thus, the point is (0, 4).

(i) To find the x-coordinates, we need to draw a parallel line on y = 3, then we need to draw a line parallel to y-axis. Thus, the line intersecting x axis given x coordinate which is (3/2, 3).

(ii) To find the y-coordinates, we need to draw a parallel line on x = - 3, then we need to draw a line parallel to x-axis. Thus, the line intersecting y axis given y coordinate which is (-3, 6).

Attachments:
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