Question

draw the graph of the equation 3x-2y=4 amd x +y -3=0.On the same graph paper,find the coordinates of the point where the two graph lines intersect.​

Answer 1

EXPLANATION.

Graph of the equation.

⇒ 3x - 2y = 4. - - - - - (1).

⇒ x + y - 3 = 0. - - - - - (2).

As we know that,

From equation (1), we get.

⇒ 3x - 2y = 4. - - - - - (1).

Put the value of x = 0 in the equation, we get.

⇒ 3(0) - 2y = 4.

⇒ - 2y = 4.

⇒ y = - 2.

Their Co-ordinates = (0,-2).

Put the value of y = 0 in the equation, we get.

⇒ 3x - 2(0) = 4.

⇒ 3x = 4.

⇒ x = 4/3.

⇒ x = 1.33.

Their Co-ordinates = (1.33,0).

From equation (2), we get.

⇒ x + y - 3 = 0. - - - - - (2).

Put the value of x = 0 in the equation, we get.

⇒ (0) + y - 3 = 0.

⇒ y - 3 = 0.

⇒ y = 3.

Their Co-ordinates = (0,3).

Put the value of y = 0 in the equation, we get.

⇒ x + (0) - 3 = 0.

⇒ x - 3 = 0.

⇒ x = 3.

Their Co-ordinates = (3,0).

Both curves intersects at a point = (2,1).

Answer 2

Given :-

3x - 2y = 4

x + y - 3 = 0

To Find :-

Co-ordinate

Solution :-

3x - 2y = 4

x + y - 3 = 0

x + y = 3

Putting x = 0 in Eq. 1

3(0) - 2y = 4

0 - 2y = 4

-2y = 4

y = 4/-2

y = -2

Co-ordinate (0,-2)

Putting y = 0

3x - 2(0) = 4

3x - 0 = 4

3x = 4

x = 4/3

Co-ordinate (4/3,0)

x + y = 3

Putting x = 0 in Eq 2

0 + y = 3

y = 3

Co-ordinate (0,3)

Putting y = 0 in Eq. 2

x + 0 = 3

x = 3

Co-ordinate (3,0)