Question

draw the graph of the equation 3x-4y=12. Find the coordinates of the points where the graph cuts a)x-axis b)y-axis​

Answer 1

Answer:

The points which cut X and the Y axis are ( 4 , 0 ) and ( 0 , -3 ) respectively.

Step-by-step explanation:

For a point which cuts the X axis will have coordinates ( a , 0 ). So we assume y = 0 for the 1st case.

$3x = 12 \\ x = 4$

So the point is ( 4 , 0 )

Similarly, when the line cuts the Y axis will have the coordinates ( 0 , a ). So we assume x = 0.

$- 4y = 12 \\ y = - 3$

The point is ( 0 , -3 )

Answer 2

The equation cuts the cuts the x axis at the co-ordinate (4,0) and the y axis at the point (-3,0).

Given:

Equation 3x-4y=12.

To Find:

The coordinates of the points where the graph cuts

a)x-axis b)y-axis​

Solution:

Given the equation 3x - 4y = 12 which can be written as,

3x - 12 = 4y    ---- (1)

After dividing (1) by 4 throughout, we get:

(3/4)x - 3 = y

Comparing the equation with the equation of a line,

y = mx + c

⇒m = 3/4

⇒c = -3

a) The graph cuts the x-axis at

in the equation (1) putting y = 0 to find where it cuts the x axis

3x - 12 = 4y

3x - 12 = 0

3x = 12

x = 4

It cuts the x axis at the co-ordinate (4,0)

b) The graph cuts the y-axis at

in the equation (1) putting x = 0 to find where it cuts the y axis

3x - 12 = 4y

0 - 12 = 4y

4y = -12

y = -3

It cuts the y axis at the point (-3,0).

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