Question

Draw the graph of the equation 4x + 3y =12 and find ther co-ordinates of the point of
intersection of the equation with the co-ordinate axes.

Answer 1

The coordinates of point intersect x-axis is (3,0).

The coordinates of point intersect y-axis is (0,4).

Step-by-step explanation:

To find : The coordinates of points where the graph of equation 4x+3y=124x+3y=12 , intersects x axis and y axis ?

Solution :

Point where the graph intersect x-axis must have its y-coordinates 0.

Putting y=0 in equation 4x+3y=124x+3y=12 ,

$4x+3\times 0=124x+3×0=12$

$4x=124x=12$

$x=\frac{12}{4}x=412$

$x=3x=3$

So point intersect x-axis is (3,0).

Point where the graph intersect y-axis must have its x-coordinates 0.

Putting x=0 in equation 4x+3y=124x+3y=12 ,

$4\times 0+3y=124×0+3y=12$

$3y=123y=12$

$y=\frac{12}{3}y=312$

$y=4y=4$

So point intersect y-axis is (0,4).

So point intersect y-axis is (0,4).Refer the attached figure below.

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