Draw the graph of the equation 4x + 7y = 28 and tell the points where the line cuts x-axis and
the y-axis
Answers
Answer :
• Point of intercept on x-axis is A(7 , 0) .
• Point of intercept on y-axis is B(0 , 4) .
Working rule :
→ Choose two or three points satisfying the given equation .
→ Mark those points on the graph paper .
→ Join those points with scale .
Solution :
Here ,
The given equation is : 4x + 7y = 28 .
• At x-axis , y-coordinate is zero .
Thus ,
Putting y = 0 in the given equation ;
We have ;
=> 4x + 7•0 = 28
=> 4x + 0 = 28
=> 4x = 28
=> x = 28/4
=> x = 7
Hence ,
The graph of the given equation will cut the x-axis at the point A(7 , 0) .
• At y-axis , x-coordinate is zero .
Thus ,
Putting x = 0 in the given equation ;
We have ;
=> 4•0 + 7y = 28
=> 0 + 7y = 28
=> 7y = 28
=> y = 28/7
=> y = 4
Hence ,
The graph of the given equation will cut the y-axis at the point B(0 , 4) .
To draw the graph :
→ Mark the points A(7 , 0) and B(0 , 4) on the graph paper .
→ Join these points with the scale .
Hence ,
The graph is obtained .
(For graph , please refer to the attachment.)
