Question

Draw the graph of the equation x+y=40. At what points the graph of the linear
equation cuts the x-axis and Y axis also find the area of the obtained closed
figure.

Answer 1

Answer:

X-axis intersect (40,0)

Y-axis intersect (0,40)

Area of the obtained closed figure = 800 sq-unit

Step-by-step explanation:

To draw the graph of the equation x+y=40.

At what points the graph of the linear

equation cuts the x-axis and Y axis,

To find the x -axis intersect,put y= 0; because any point on X-axis has y=0

$x + 0 = 40 \\ \\ x = 40$

point A(40,0); x-intersect

To find the y -axis intersect,put x= 0; because any point on y-axis has x=0

$0 + y = 40 \\ \\ y = 40$

point B(0,40); Y-axis intersect

To find the area of the obtained closed

figure ; ∆ABC

$= \frac{1}{2} \times base \times height \\ \\ = \frac{1}{2} \times AC \times BC\\ \\ = \frac{1}{2} \times 40 \times 40 \\ \\ = 800 \: {unit}^{2}$

Hope it helps you.

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