draw the graph of the equation y-22=4. comment on : i) x = 0, y = 4 is a solution of the equation. (ii x = 1, y = 5 is a solution of equation (iii) (4-4), lies on the graph of (iv) area of the triangle formed by the line y-2x=4 and the coordinate axis
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(i)x=0,y=4
L.H.S=y−2x=4−2×0=4−0=4
So,x=0,y=4 is a solution of the equation y−2x=4
(ii)x=1,y=5
L.H.S=y−2x=5−2×1=5−2=3=R.H.S
So,x=1,y=5 is not a solution of the equation y−2x=4
(iii)x=−4,y=−4
L.H.S=−4−2×−4=−4+8=4=R.H.S
So, (−4,−4) lies on the graph of the equation y−2x=4
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