Question

draw the graph of the equation y=5x

Answer 1

Answer and Explanation: In the equation y=5xthe slope (m) is 5, and the y-intercept is the point (0,0) since there is nothing added or subtracted to the 5x, and thus b = 0. To graphthis line you would first place a point at the y-intercept of (0,0).

Answer 2

$\large{\underline{\bf{Explanation-}}}$

Given equation : y = 5x

For finding solutions, we have to put different values,

★ put x = 1

=> y = 5 × 1

=> y = 5

_________________

★ put x = 0

=> y = 5 × 0

=> y = 0

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★ Put x = -1

=> y = 5 × (-1)

=> y = - 5

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Solutions of this equation :

$\begin{array}{| c | c | c | c |}\cline{1-4} x & -1 & 1 & 0 \\ \cline{1-4}y & -5 & 5 & 0 \\\cline{1-4} \end{array}$

Graph :

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(12.6,5.9){ X }\put(6.,5.9){ X' }\put(9.45,9.3){ Y }\put(9.4,2.5){ Y' }\put(9.5,6){\vector(1,0){3}}\put(9.5,6){\vector(-1,0){3}}\put(9.5,6){\vector(0,1){3}}\put(9.5,6){\vector(0,-1){3}}\put(9.9,5.9){\line(0,1){0.2}}\put(10.3,5.9){\line(0,1){0.2}}\put(10.7,5.9){\line(0,1){0.2}}\put(11.1,5.9){\line(0,1){0.2}}\put(11.5,5.9){\line(0,1){0.2}}\put(11.9,5.9){\line(0,1){0.2}}\put(9.1,5.9){\line(0,1){0.2}}\put(8.7,5.9){\line(0,1){0.2}}\put(8.3,5.9){\line(0,1){0.2}}\put(7.9,5.9){\line(0,1){0.2}}\put(7.5,5.9){\line(0,1){0.2}}\put(7.1,5.9){\line(0,1){0.2}}\put(9.4,6.4){\line(1,0){0.2}}\put(9.4,6.8){\line(1,0){0.2}}\put(9.4,7.2){\line(1,0){0.2}}\put(9.4,7.6){\line(1,0){0.2}}\put(9.4,8){\line(1,0){0.2}}\put(9.4,8.4){\line(1,0){0.2}}\put(9.4,5.6){\line(1,0){0.2}}\put(9.4,5.2){\line(1,0){0.2}}\put(9.4,4.8){\line(1,0){0.2}}\put(9.4,4.4){\line(1,0){0.2}}\put(9.4,4){\line(1,0){0.2}}\put(9.4,3.6){\line(1,0){0.2}}\put(11.4,5.6){ 5 }\put(7.15,5.6){ -5 }\put(9.2,7.9){ 5 }\put(9.6,3.9){ -5 }\put(9.5,6){\circle*{0.15}}\put(9.5,6){\circle{0.3}}\put(9.9,8){\circle*{0.15}}\put(9.9,8){\circle{0.3}}\put(9.1,4){\circle*{0.15}}\put(9.1,4){\circle{0.3}}\put(9.5,6){\line(1,5){0.7}}\put(9.5,6){\line(-1,-5){0.7}}\end{picture}$