Draw the graph of the equations x-y+1=0 and 3x+2y-12=0 Determine the coordination of the vertices of the triangle formed these lines and the x-axis and shade the triangular region
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First equation is x – y + 1 = 0
Add y and subtract 1 both side we get
x = y -1
Plug y = 0 ,1 and 2 we get
x = 0 -1 = - 1
x = 1 -1 = 0
x = 2 -1 = 1
X. -1. 0. 1.
Y. 0. 1. 2.
3x + 2y – 12 = 0
Subtract 3x and add 12 both side we get
2y = 12 – 3x
Divide by 2 we get
y = 6- 1.5 x
Plug x = 0 ,2, and 4 we get
y = 6- 1.5 *0 = 6
y = 6- 1.5 *2 = 3
y = 6- 1.5 *4 = 0
X. 0. 2. 4.
Y. 6. 3. 0.
We can see from the graphs (given above) that points of intersection of the lines with the x–axis are (–1, 0), (2, 3) and (4, 0).
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