Question

Draw the graph of the equations x-y+ 1=0 and 3x+2y-12= 0. Using this graph, find the values of x and y which satisfy both the equations.

Answer 1

this question came in 10th board also
so, x=2 and y=3 since it is a common solution ..A1/A2not equal to B1/B2 ,it is a intersecting lines on finding solutions x=2 and y=3 satisfies both these equation

Answer 2

The values of x=2 and y=3 which satisfy both the equations.

Step-by-step explanation:

Given : Equation $x-y+1=0$ and $3x+2y-12=0$

To find : Draw the graph of the equations. Using this graph, find the values of x and y which satisfy both the equations ?

Solution :

Equation $x-y+1=0$ plotted with red line passion through (-1,0) and (0,1).

Equation $3x+2y-12=0$ plotted with blue line passion through (4,0) and (0,6).

The values of x and y which satisfy both the equations is the intersection point.

The intersection point is (2,3).

Therefore, the values of x=2 and y=3 which satisfy both the equations.

#Learn more

Draw the graph of equation 5x+3y=4 and check whether

a) x=-2, y=5

b) x=-1, y=3 are solutions

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