Question

Draw the graph of the following equations on the same graph.

2x + y = 160; 4x + 2y = 300

Also mention the coordinate of the point of intersection of these lines.

Answer 1

Answer:

Here is your Solution..

Maybe I am Correct.

Answer 2

The system of equations have no solution.

Explanation:

Given that the system of equations are $2x+y=160$ and $4x+2y=300$

Let us plot the equation $2x+y=160$

When $x=0 \implies y=160$

When $y=0 \implies 2x=160 \implies x=80$

Plotting the coordinates (0,160) and (80,0) and joining them in the graph, we get, the line for the equation $2x+y=160$

Now, we shall plot the equation $4x+2y=300$

When $x=0 \implies 2y=300 \implies y=150$

When $y=0 \implies 4x=300 \implies x=75$

Plotting the coordinates (0,150) and (75,0) and joining them in the graph, we get, the line for the equation $4x+2y=300$

Solution:

Let us solve the equation by elimination method.

Multiplying the equation $2x+y=160$ by -2 and adding the equations, we have,

$-4x-2y=-320\\ 4x+2y=300\\--------\\0=-20$

Since $0\neq -20$, the equations have no solution.

Thus, the solution of the system of equations is no solution.

Learn more:

(1) Solve the following system of equations graphically: 4x – 5y + 16 = 0, 2x + y = 6 Determine the vertices of the triangle formed by these lines and the x-axis

brainly.in/question/4224924

(2) Draw the graph of the follwing equations :

2x-y-2=0

4x-3y-24=0

y+4=0

obtain the vertices of the triangle so obtained AND ALSO FIND THE AREA OF THE TRIANGLE

brainly.in/question/3591883