Draw the graph of the following function.
B) y=x+2, XER-{2
Answers
Answer:
Explanation:
Answer
Method 1:
Prepare a table of value to y=x
2
−x−2.
x −2 −1 0 1 2
y 4 0 −2 −2 0
Draw the parabola. Write the coordinates of the intersecting point of the parabola with x-axis.
Note the co-ordinates of the intersecting points of the parabola with x-axis.
The coordinates where the parabola intersects the x-axis are the roots of the equation.
That coordinates are B(−1,0) and E(2,0).
∴ The roots are x=−1 and x=2
Method 2:
x
2
−x−2=0⇒x
2
=x+2
Consider y=x
2
and y=x+2
For y=x
2
x −2 −1 0 1 2
y 4 1 0 1 4
For y=x+2
x 0 1 −1 2 −2
y 2 3 1 4 0
Draw the parabola and linear graph
Write the coordinates of the points where the straight line intersects with the parabola.
They are B(−1,1) and E(2,4).
∴ The roots are x=−1 and x=2.
